Need a force to accelerate an object on a frictionless surface

AI Thread Summary
To accelerate an object on a frictionless surface, a force is indeed required, as per Newton's Second Law (F=MA). The discussion emphasizes that even in the absence of friction, an external force must be applied to change the object's state of motion. Calculating the necessary force involves using the equation F=MA, where M is the mass of the object and A is the desired acceleration. Newton's First Law is also relevant, as it states that an object at rest will remain at rest unless acted upon by a force. Understanding these principles is crucial for analyzing motion in physics.
DavidMasabo
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Homework Statement
would you need a force to accelerate an object on a friction-less surface?
How could one calculate the force?
Relevant Equations
F=MA
Problem Statement: would you need a force to accelerate an object on a friction-less surface?
How could one calculate the force?
Relevant Equations: F=MA

would you need a force to accelerate an object on a friction-less surface?
How could one calculate the force?
 
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DavidMasabo said:
Problem Statement: would you need a force to accelerate an object on a friction-less surface?
How could one calculate the force?
Relevant Equations: F=MA

Problem Statement: would you need a force to accelerate an object on a friction-less surface?
How could one calculate the force?
Relevant Equations: F=MA

would you need a force to accelerate an object on a friction-less surface?
How could one calculate the force?
Welcome to the PF.

Looks like you answered your own question by listing the Relevant Equation... :smile:
 
David - Revise Newtons First Law.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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