Need formula to relate distance to arcsec in the sky

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To determine how long it takes for a supernova explosion to appear as one arcsecond from Earth at a distance of 50 kiloparsecs, a formula relating distance and angular size is needed. The circumference at this distance can be calculated using the formula Pi times diameter, then converting to arcseconds. A suggested formula is D = H/2tan(a), but its applicability is questioned. The expansion rate of the supernova debris, which travels at speeds close to the speed of light, is crucial for calculating the time. Understanding the geometry of the situation and the relevant formulas is essential for solving the problem.
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Homework Statement


I need to find how long it will take a supernova explosion to be a size of one arc sec here on earth, the distance to this explosion is 50 kilparsec


Homework Equations





The Attempt at a Solution


Any clue on what the formula is?
thanks
 
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leonne said:

Homework Statement


I need to find how long it will take a supernova explosion to be a size of one arc sec here on earth, the distance to this explosion is 50 kilparsec

Wiki defines the kiloparsec at http://en.wikipedia.org/wiki/Parsec so you can get the circumference at 50 kpc using Pi*d. Then divide by 360 to get degrees, 60 to get minutes, and 60 again to get seconds.
 
hmm, don't think that will help me I need to find how big the explosion needs to be to see 1 arc sec. With the radius, than i can calculate the time. I found this formula D=H/2tan(a) , but don't think it will work. either hmm. Well if I solve for H would that be the true diameter of the explosion?
Well thanks for the help
 
Have you tried drawing a diagram to see what the geometry of the situation is?

Things to keep in mind for very small angles: θ ≈ sin(θ) ≈ tan(θ).

You're looking for the time it takes "a supernova explosion to be a size of one arc sec [as seen] here on earth". What were you planning on using for the expansion rate of the supernova debris?
 
hey,
well i remembered using a formula last semester to find something similar, but forgot what the formula was. I found what the velocity was in part 1.
 
leonne said:
hey,
well i remembered using a formula last semester to find something similar, but forgot what the formula was. I found what the velocity was in part 1.

The shockwave of a supernova propagates at approximately the speed of light. I would suspect that's visible.
 
well we where told that ...ejected mass of 20 solar mass.
 
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