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Dry steam is compressed isothermally from 1 bar to 4 bar, with an initial volume of 0.5 m³. The ideal gas law can be applied, specifically using the equation P1V1 = P2V2, since the temperature remains constant. The calculation for the final volume after compression involves substituting the known values into the equation. It is important to consider whether the steam remains in a vapor state or if condensation occurs at intermediate pressures. The discussion emphasizes the need for clarity on temperature and superheat to accurately determine the final volume.
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Homework Statement


Dry steam is compressed isothermally from a pressure of 1 bar to 4 bar. if the initial volume is 0.5 m^3, calculate the volume of the steam after compression

Homework Equations



Dont know

The Attempt at a Solution

 
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naim said:
Dry steam is compressed isothermally …

it means with the temperature staying constant :wink:

(from the greek "iso-", meaning "same")
 
so how do i calculate it , does anyone know the equation of how to do it?
 
Since this is dry (completely vapor state) you could model with the ideal gas law

PV=nRT

since it is isothermal T is does not change, therefore: n,R, and T are all constant and the right side of the equation is the same before and after compression, so
P1V1=P2V2

V2 = (P1V1)/P2 , plug and chug
 
do i convert the 1 bar ? or do i just keep it as
v2=(1x0.5)/4 ?
 
naim said:

Homework Statement


Dry steam is compressed isothermally from a pressure of 1 bar to 4 bar. if the initial volume is 0.5 m^3, calculate the volume of the steam after compression


Homework Equations



Dont know

The Attempt at a Solution

Is there anymore information, e.g., the temperature, or the amount of superheat? Using the ideal gas law, or Boyle's law would be appropriate for an approximation. If the temperature is at a saturation level between 1 bar and 4 bar, then at the intermediate pressure, there would be some condensation (vapor to liquid transformation).
 
no that was all the information that was given
 
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