Need Help with Thermo Energy Transfer problem

AI Thread Summary
The discussion revolves around calculating the temperature difference across a 0.2-meter-thick concrete wall, given a steady-state energy transfer rate of 0.15 kW per square meter. Participants clarify that the heat flux, represented as Qx, is the rate of heat transfer per unit area, which remains 0.15 kW for the entire 1 m² area. The correct approach involves using Fourier's law to relate the heat transfer rate to the temperature difference across the wall. Additionally, it is emphasized that the thermal conductivity coefficient (k) for concrete is necessary for accurate calculations. Understanding these concepts is crucial for solving the problem effectively.
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A 0.2-m-thick plane wall is constructed of concrete. At steady state the energy transfer rate by conduction through a 1-m^2 area of the wall is 0.15 kW. If the temperature distibution is linear through the wall, what is the temperature difference across the wall, in K?

i don't even know where to start, anything will help...
 
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I have been doing some work on this.. and i have came up with an answer, I am pretty sure its not right though..

Using Fourier's law:

Qx= -kA[T2-T1/L]

we know that the Qx is .15kW per 1 m^2, and the thickness of the concrete plane is .2 m

If .15kW of energy enter 1.0 m^2, then only .03 kW enter the area of .2 m??

right now i have .03kW= -k(T2-T1/ .2m)

im stuck..
 
If .15kW of energy enter 1.0 m^2, then only .03 kW enter the area of .2 m??

Why is this? I don't think you understand the concept of "heat flux" which you represent as Qx. Heat flux is the rate of heat transferred given an area. In math form thats

q" = \frac{dQ}{dt} = Qx

So if you have 0.15kw of energy being transferred over 1m^2 of area, what is your heat flux going to be?

You are also going to need to look up the transfer coefficient (k) for concrete. I imagine this is in your book somewhere.
 
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