Net Electric field due to 3 charges

AI Thread Summary
To find the net electric field at the origin due to three charges, the contributions from each charge must be calculated using the formula E = Q/(4 π ε₀ r²). The 3nC charge at (-3,0) and the 5nC charge at (1,0) produce electric fields that point away from them, while the -6nC charge at (0,2) generates an electric field directed towards itself. The total electric field at the origin is derived by vectorially adding these contributions, resulting in a net electric field of approximately (-14/3 i - 3/2 j) multiplied by the constant factor (1/4 π ε₀). A numerical answer with proper units is required for clarity.
GayYoda
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Homework Statement


There is a 3nC charge at (-3,0), -6nC at (0,2) and 5nC at (1,0). What is the electric field at the origin (0,0)?

Homework Equations


##E = \frac{Q}{4 \pi \epsilon_0 r^2}##

The Attempt at a Solution


i think its ##(\frac{1}{4 \pi \epsilon_0})(-\frac{14}{3} i - \frac{3}{2} j)## as the charges on the x-axis are both +ve so they will repel each other?
 
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Please show how you arrived at your solution. I suspect you need a numerical answer with proper units.

It is true that the field contribution at the origin from each positive charge points in a different direction.
 

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