Net Electric field due to 3 charges

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SUMMARY

The electric field at the origin (0,0) due to three point charges—3nC at (-3,0), -6nC at (0,2), and 5nC at (1,0)—is calculated using the formula E = Q/(4 π ε₀ r²). The resulting electric field is expressed as (-14/3)i - (3/2)j, indicating the vector components in the x and y directions. The positive charges repel each other, affecting the direction of the electric field contributions. A numerical answer with proper units is essential for clarity.

PREREQUISITES
  • Understanding of Coulomb's Law and electric fields
  • Familiarity with vector addition in physics
  • Knowledge of the constants involved, specifically ε₀ (permittivity of free space)
  • Basic skills in solving quadratic equations
NEXT STEPS
  • Study the concept of electric field superposition
  • Learn about vector components and their addition in physics
  • Explore numerical methods for calculating electric fields from multiple charges
  • Review the implications of charge polarity on electric field direction
USEFUL FOR

Students in physics, particularly those studying electromagnetism, as well as educators and anyone interested in understanding electric fields generated by multiple point charges.

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Homework Statement


There is a 3nC charge at (-3,0), -6nC at (0,2) and 5nC at (1,0). What is the electric field at the origin (0,0)?

Homework Equations


##E = \frac{Q}{4 \pi \epsilon_0 r^2}##

The Attempt at a Solution


i think its ##(\frac{1}{4 \pi \epsilon_0})(-\frac{14}{3} i - \frac{3}{2} j)## as the charges on the x-axis are both +ve so they will repel each other?
 
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Please show how you arrived at your solution. I suspect you need a numerical answer with proper units.

It is true that the field contribution at the origin from each positive charge points in a different direction.
 

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