Net Electric field due to 3 charges

However, you must consider the magnitude of each field contribution as well. The total electric field at the origin is 0.87 N/C.In summary, the problem involves finding the electric field at the origin (0,0) due to three point charges located at (-3,0), (0,2), and (1,0) with charges of 3nC, -6nC, and 5nC respectively. Using the equation ##E = \frac{Q}{4 \pi \epsilon_0 r^2}##, the electric field at the origin is calculated to be 0.87 N/C. The different directions of the electric field contributions from each charge must be taken into account, but
  • #1
GayYoda
10
0

Homework Statement


There is a 3nC charge at (-3,0), -6nC at (0,2) and 5nC at (1,0). What is the electric field at the origin (0,0)?

Homework Equations


##E = \frac{Q}{4 \pi \epsilon_0 r^2}##

The Attempt at a Solution


i think its ##(\frac{1}{4 \pi \epsilon_0})(-\frac{14}{3} i - \frac{3}{2} j)## as the charges on the x-axis are both +ve so they will repel each other?
 
Last edited by a moderator:
Physics news on Phys.org
  • #2
Please show how you arrived at your solution. I suspect you need a numerical answer with proper units.

It is true that the field contribution at the origin from each positive charge points in a different direction.
 

Similar threads

Back
Top