Net force =0 or Net force =GM^2/4R^2....?

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SUMMARY

The net force acting on two stars of equal mass M in a circular orbit of radius R around their common center of mass is calculated as GM^2/4R^2. This force is not zero despite the system being in translational equilibrium because the stars are in constant circular motion, which requires a centripetal force. Newton's laws of motion confirm that a net force is necessary to maintain this circular trajectory.

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BLUE PEARL
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Two stars of equal mass M move with constant speed V in a circular orbital of radius R about their common center of mass .What is the net force on each star?the answer to this question was net force=GM^2/4R^2 .I want to ask that why net force not equal to zero although it is in translational equilibrium?

Any help in this regard would be appreciated...Thank You in anticipation
 
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BLUE PEARL said:
Two stars of equal mass M move with constant speed V in a circular orbital of radius R about their common center of mass .What is the net force on each star?the answer to this question was net force=GM^2/4R^2 .I want to ask that why net force not equal to zero although it is in translational equilibrium?

Any help in this regard would be appreciated...Thank You in anticipation

If something is in a circular orbit, how can the force on it be 0? Newton's first/second laws apply.
 

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