Net force given 40 degree angle, coef. of kinetic friction=.3, and mass=80kg

AI Thread Summary
To calculate the net force acting on an 80 kg mass at a 40-degree angle with a coefficient of kinetic friction of 0.3, it is essential to resolve the applied force into horizontal and vertical components. The weight of the mass is determined by W = mg, which influences the normal force and subsequently the frictional force, calculated as f = μmg. The direction of the angle (above or below the horizontal) significantly affects the calculations. When the horizontal applied force surpasses the frictional force, the net force (Fnet) results in the mass accelerating. Understanding these relationships is crucial for solving the problem effectively.
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Homework Statement



angle is in relation to horizontal

Homework Equations


f net=m*a


The Attempt at a Solution



yikes! i don't know!

i appreciate ANY help!
 
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Please write one's work and show an attempted solution. Is the angle above or below the horizontal - it makes a difference.

Please refer to - http://hyperphysics.phy-astr.gsu.edu/hbase/N2st.html#c2 - for some ideas.

A mass m has weight W = mg, and that weight (which is normal to the horizontal) will have a friction force f = \mumg, where \mu = coefficient of friction.

Now the external (applied) force at a angle can be resolved into horizontal and vertical forces.

When the horizontal applied force exceeds friction, the net force (Fnet causes the mass m to accelerate a.
 

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