Newton's Cradle: Explaining 2-Ball vs. 1-Ball Dynamics

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In Newton's Cradle, when one ball is released, it transfers its momentum and energy to the stationary balls, resulting in one ball popping out on the opposite side. When two balls are pulled back and released, they collide with the stationary balls, and due to conservation of momentum and energy, two balls exit rather than one at double the speed. The momentum before and after the collision must remain equal, and the kinetic energy of two balls moving at speed v is greater than that of one ball moving at speed 2v. This discrepancy in energy explains why only two balls can be ejected instead of one with increased speed. Understanding these principles clarifies the mechanics behind the behavior of Newton's Cradle.
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when one ball is pulled out, released, and collides with the other four in Newton's Cradle, one ball will pop out the other side. Likewise, when two balls are pulled back, two balls will pop out the other side. Why doesn't one ball pop out, but with twice the speed?

You are to use the concepts of conservation of momentum and conservation of energy to mathematically show that only two balls may be ejected on the other side when two balls are pulled back instead of one ball with twice the speed.i know that both momentum and energy are both conserved because the collisons are elastic, but i just get stuck there

P initial=P finalany help would be appreciated
 
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Compare the energy of two balls with speed v to the energy of one ball with speed 2v. Are they the same?
 
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