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Homework Statement
Two uniform masses of .260kg are fixed at points A and B. Find the magnitude and direction of the initial acceleration of a uniform sphere with mass 0.01kg released from rest at point P that is acted on the gravitational forces of attraction from spheres A and B.
The diagram shows the spheres arranged in a triangle. If you were to divide the triangle in half, making two IDENTICAL right angles triangles, you would have a hypotenuse of 10cm, x value of 8cm, and y value of 6 cm.
Homework Equations
F=G Mm/r^2
G=6.67x10^-11
F=ma
The Attempt at a Solution
The x values cancel as vectors are equal in magnitude and opposite in direction.
This leaves the y values. Solve for F between mass of 0.26kg and 0.01kg.
F=(6.67x10^-11)(0.26)(0.01)/(0.06^2m)
=4.8x10^-11
Multiply this by two because there are two identical masses acting on the sphere at point P
=9.63x10^-11
Now, using F=ma, equate the result to this...
9.63x10^-11=ma
9.63x10^-11=(0.01)a
divide 9.63x10^-11 by .01
a=9.0x10^-9
This is wrong... the correct answer should be 2.1x10^-9
Thanks :)
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