Newtons Law / Kinematic problem?

AI Thread Summary
The discussion revolves around solving a kinematic problem involving an 8.00 kg block of ice sliding down a frictionless ramp. The initial approach used kinematics to determine the acceleration, resulting in a calculated angle of 9.6 degrees. However, a classmate arrived at a different angle of 12.275 degrees, prompting confusion. It was suggested that the problem could also be approached through conservation of energy, despite the class not yet covering this topic. The user ultimately realized that a simple arithmetic error in their calculations led to the incorrect angle.
physstudent1
Messages
267
Reaction score
1
Hello, the question I'm having trouble with is:

"A 8.00kg block of ice, released from rest at the top of a 1.5 m long frictionless ramp, slides downhill, reaching a speed of 2.5 m/s at the bottom.
What is the angle between the ramp and the horizontal?"

My first attempt to solve this problem was that I would use kinematics to get the acceleration. And then use the acceleration and Newton's laws to find the angle. By using kinematics I got the equation 2.5^2 = 0 + 2(a)(1.5)
I then got a to be 1.64. Using that I set the equation 8gsin(theta) = 1.64(8). Eventually getting theta to equal 9.6 degrees. But when I compared my answer to the a fellow classmate He got 12.275, but I can't really follow his work and there's no answer in the back of the book, so can anyone help?
 
Physics news on Phys.org
Since there is no friction, it may be easier to consider this problem as a conservation of energy problem.
 
We have not gotten to energy yet in my class :(. This is the third chapter all we have done is kinematics, projectile motion, and now this.
 
I've just looked through your work and it appears it's just your arithmetic that's letting you down. Your kinematic equation is correct, but your value for acceleration is not; try solving for acceleration again.
 
Ah jeez I'm so dumb thanks alot! I just have sloppy hand writting so I turned the 1.5 into a 1.9 which gave me the wrong answer thanks alot.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top