Newton's Laws and coefficient of static friction

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SUMMARY

The maximum horizontal force that can be applied to a 5.00-kg block resting on a 12.0-kg block, with a coefficient of static friction of 0.600, is determined by the normal force acting on the 5.00-kg block. When the force is applied to the 12.0-kg block, the maximum force before slipping occurs is 29.4 N, while applying the force to the 5.00-kg block results in a maximum force of 24.5 N. The force of friction does not have the same magnitude in both scenarios, as it is dependent on the normal force exerted by the 5.00-kg block in each case.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Knowledge of static friction and its coefficient
  • Familiarity with normal force calculations
  • Basic principles of force and motion
NEXT STEPS
  • Calculate the maximum static friction force using the formula: F_friction = μ * N
  • Explore the implications of applying forces to different masses in a frictional system
  • Study the effects of varying coefficients of friction on block motion
  • Investigate real-world applications of static friction in engineering scenarios
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Physics students, educators, and anyone interested in understanding the principles of static friction and Newton's Laws of Motion.

jehan4141
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A 5.00-kg block is placed on top of a 12.0-kg block that rests on a frictionless table. The coefficient of static friction between the two blocks is 0.600. What is the maximum horizontal force that can be applied before the 5.00-kg block begins to slip relative to the 12.0-kg block, if the force is applied to (a) the more massive block and (b) the less massive block?

In this problem does the force of friction have the same magnitude in both A and B? My logic is that it is only the normal force of the small mass that cause the friction in both cases. Is this correct?
 
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jehan4141 said:
A 5.00-kg block is placed on top of a 12.0-kg block that rests on a frictionless table. The coefficient of static friction between the two blocks is 0.600. What is the maximum horizontal force that can be applied before the 5.00-kg block begins to slip relative to the 12.0-kg block, if the force is applied to (a) the more massive block and (b) the less massive block?

In this problem does the force of friction have the same magnitude in both A and B? My logic is that it is only the normal force of the small mass that cause the friction in both cases. Is this correct?

Your assertion about normal force seems sound.
 

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