Newton's Laws of Motion - Force Problem

AI Thread Summary
The discussion revolves around calculating the average force exerted by a target on an arrow and vice versa, using Newton's laws of motion. The user calculated the acceleration of the arrow upon impact and found the net force exerted by the target to be approximately 435 N. Clarification was sought on whether this force is correct and how to determine the force the arrow exerts on the target. It was confirmed that the target applies a force of 435 N to the left, and the arrow exerts an equal and opposite force on the target. The conversation emphasizes understanding the action-reaction principle in the context of the problem.
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Homework Statement


A 0.075-kg arrow hits the target at 21 m/s and penetrates 3.8cm before stopping. (a) What average force did the target exert on the arrow? (b) What average force did the arrow exert on the target? (c) An identical arrow strikes the target at 42m/s. If the target exerts the same average force as before, what's the penetration depth?

Known: mass: .075kg velocity (?) 21m/s, displacement: 3.8cm

Homework Equations


Here I am a little confused. (Or a lot confused)
Fnet=m x a

a=velocity final squared - velocity initial squared / 2(Δ)? Not sure if this equation applies

The Attempt at a Solution


I used the equation to figure out the acceleration since I have the mass. So here is where I am at:
a=0-(21m/s)2 / 2(.038m) = -5.8 x 10^3 m/s2

Then I used that to find Fnet=m x a = (.075kg)(-5.8 x 10^3m/s2)= -435N

I feel like I am on a completely wrong track and am not sure how to answer the question. Is the target applying a force of -435N?

Any help in the right direction is greatly appreciated, thank you for your time.

V/r
Jesse
 
Physics news on Phys.org
Looks good! Yes , if the arrow is moving left to right, the target applies a force on the arrow of 435 N to the left. What force and in what direction does the arrow apply on the target?
 
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