What is the Tension in a Pulley System with Two Connected Masses?

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The discussion focuses on calculating the tension in a pulley system with two connected masses, m1 and m2. The first mass, m1, is 1.378 kg and moves on a frictionless surface, while m2 weighs 0.872 kg and is affected by gravity. The equations of motion for both masses are established, leading to the determination of acceleration as 3.8 m/s². By substituting this acceleration back into the tension equation, the final tension in the string is calculated to be 5.24 N. The approach taken in solving the problem is confirmed as correct.
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Homework Statement


[PLAIN]http://img703.imageshack.us/img703/3580/12p71.jpg
m1 = 1,378 g. It is free to move along a horizontal, frictionless surface. This block is connected to a second block with mass of m2 = 872 g by a massless string that extends around a massless, frictionless pulley. Find the tension of the string.

Homework Equations



F net = ma since the system is not at equilibrium.

The Attempt at a Solution



So for m1,
Tension (T) = 1.378 kg*a.

for m2,
mg-T = m2*a
T = 8.55 N - 0.827 kg*a

since tension is equal at any point along the string, i equated both equations and isolate acceleration;
1.378 kg*a = 8.55 N - 0.872 kg*a
a = 3.8 m/s^2.

therefore T = 1.378 kg * 3.8 m/s^2 = 5.24 N.

did i approach this question properly?
 
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Looks good to me. If you go <a href="https://www.physicsforums.com/showthread.php?t=220910">here</a>, there's an example for pulleys in the pdf.
 
oops, no html. just cut and paste.
 
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