Newton's Second Law for a Single Force

AI Thread Summary
To determine the minimum strength required for a fishing line to stop a salmon weighing 85 N in 11.6 cm while initially moving at 3.0 m/s, the acceleration was calculated to be -38.7931 m/s². The mass of the salmon was found to be approximately 8.673 kg. Using Newton's second law, the force was calculated as F = ma, resulting in a force of -336.45 N. The negative sign indicates a direction opposite to the salmon's drift velocity, suggesting the fishing line's tension must be positive to effectively stop the fish. The calculations highlight the importance of direction in force applications in physics problems.
djester555
Messages
10
Reaction score
0

Homework Statement


Stopping a Salmon The tension at which a fishing line snaps is commonly called the line's "strength." What minimum strength is needed for a line that is to stop a salmon of weight 85 N in 11.6 cm if the fish is initially drifting at 3.0 m/s? Assume a constant acceleration.


Homework Equations


X1= -0
X2= .116
V1 = 3.0
V2= 0
A = unknown
T = unknown
T =

The Attempt at a Solution


Solved for A and found it to be -38.7931

m = 85 / 9.8


F = ma
F= (8.673)(-38.793)
F = - 336.45
Not sure what i did wrong
 
Physics news on Phys.org
Fishing line may not be in the direction of drift velocity of salmon.
 
so that would swithch the sign to positive then
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top