Newton's Second Law Particle Problem

AI Thread Summary
A particle is moving at a constant velocity of v = (3 m/s)i - (4 m/s)j while two forces act on it, one being F1 = (2N)i + (-6N)j. Since the acceleration is zero due to constant velocity, the net force must also be zero. The second force can be determined by setting the net force equal to zero, leading to the conclusion that the other force is F2 = (-2N)i + (6N)j. This balance of forces confirms that the system is in equilibrium. Understanding that constant velocity implies no net force is crucial for solving such problems.
Seraph404
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Homework Statement



While two forces act on it, a particle is to move at the constant velocity v = (3 m/s)i - (4 m/s)j. One of the forces is F1 = (2N)i + (-6N)j. What is the other force?


Homework Equations



Fnet = ma


The Attempt at a Solution



Well, I'm really just wanting a hint. I know that the acceleration is zero because the velocity is constant. So how do I use velocity to find the second force? Surely I'm missing something fundamental here. Once again, just a hint would be nice.
 
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Seraph404 said:

Homework Statement



While two forces act on it, a particle is to move at the constant velocity v = (3 m/s)i - (4 m/s)j. One of the forces is F1 = (2N)i + (-6N)j. What is the other force?


Homework Equations



Fnet = ma


The Attempt at a Solution



Well, I'm really just wanting a hint. I know that the acceleration is zero because the velocity is constant. So how do I use velocity to find the second force? Surely I'm missing something fundamental here. Once again, just a hint would be nice.
You pretty much gave yourself a hint when you said that there is no net force. Since one of the two forces are given, what's the other one?
 
PhanthomJay said:
You pretty much gave yourself a hint when you said that there is no net force. Since one of the two forces are given, what's the other one?


(-2N)i + (6N)j ?
 
Seraph404 said:
(-2N)i + (6N)j ?
Correct! (the answer would be the same regardless of the value of the constant velocity).
 
Oh okay! Thanks!
 
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