1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Newton's Third Law - Using pulleys and slopes

  1. May 21, 2009 #1
    1. The problem statement, all variables and given/known data
    A 5.9 kg box is on a frictionless 40 degree slope and is connected via a massless string over a massless, frictionless pulley to a hanging 2.1 kg weight.

    A.
    What is the tension in the string if the 5.9 kg box is held in place, so that it cannot move?

    B.
    If the box is then released, which way will it move on the slope?

    C.
    What is the tension in the string once the box begins to move?

    2. Relevant equations
    Fnet=m*a


    3. The attempt at a solution
    A. The mass of the second box times the gravity will give me the solution to part A -> m2*(9.81)=20.61N
    B. If the box is released then it will slide downwards on the slope because there is more mass in m1
    C. This is where I'm stuck. My professor wrote down this equation for us to follow.

    -m1*g*sin[tex]\theta[/tex]+T=m1(-a)
    and
    m2*g*T=m2(a)

    but I don't know where to go from here.
     
  2. jcsd
  3. May 21, 2009 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Hi tastypotato! :smile:

    (have a theta: θ :wink:)
    Sorry, but that's the wrong reason … "more mass" doesn't clinch it … what matter is the equation your professor wrote down for you …
    (and btw, this is https://www.physicsforums.com/library.php?do=view_item&itemid=26", not third)

    These two equations are the Ftotal = ma equations for m1 and m2 separately

    (you have to do them separately) …

    the first one is of the components in the direction of the slope, and the second is for the vertical components …

    a is the same in both equations because the string has fixed length, so if m1 goes distance x up the slope, m2 goes distance vertically down …

    so i] can you prove those two equations are correct?

    ii] eliminate T, and find a :smile:
     
    Last edited by a moderator: Apr 24, 2017
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Newton's Third Law - Using pulleys and slopes
Loading...