- #1

- 3

- 0

## Homework Statement

A 5.9 kg box is on a frictionless 40 degree slope and is connected via a massless string over a massless, frictionless pulley to a hanging 2.1 kg weight.

A.

What is the tension in the string if the 5.9 kg box is held in place, so that it cannot move?

B.

If the box is then released, which way will it move on the slope?

C.

What is the tension in the string once the box begins to move?

## Homework Equations

F

_{net}=m*a

## The Attempt at a Solution

A. The mass of the second box times the gravity will give me the solution to part A -> m

_{2}*(9.81)=20.61N

B. If the box is released then it will slide downwards on the slope because there is more mass in m

_{1}

C. This is where I'm stuck. My professor wrote down this equation for us to follow.

-m

_{1}*g*sin[tex]\theta[/tex]+T=m

_{1}(-a)

and

m

_{2}*g*T=m

_{2}(a)

but I don't know where to go from here.