• Support PF! Buy your school textbooks, materials and every day products Here!

Newton's Third Law - Using pulleys and slopes

  • #1

Homework Statement


A 5.9 kg box is on a frictionless 40 degree slope and is connected via a massless string over a massless, frictionless pulley to a hanging 2.1 kg weight.

A.
What is the tension in the string if the 5.9 kg box is held in place, so that it cannot move?

B.
If the box is then released, which way will it move on the slope?

C.
What is the tension in the string once the box begins to move?

Homework Equations


Fnet=m*a


The Attempt at a Solution


A. The mass of the second box times the gravity will give me the solution to part A -> m2*(9.81)=20.61N
B. If the box is released then it will slide downwards on the slope because there is more mass in m1
C. This is where I'm stuck. My professor wrote down this equation for us to follow.

-m1*g*sin[tex]\theta[/tex]+T=m1(-a)
and
m2*g*T=m2(a)

but I don't know where to go from here.
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
25,832
249
Hi tastypotato! :smile:

(have a theta: θ :wink:)
A 5.9 kg box is on a frictionless 40 degree slope and is connected via a massless string over a massless, frictionless pulley to a hanging 2.1 kg weight.

B.
If the box is then released, which way will it move on the slope?

C.
What is the tension in the string once the box begins to move?

B. If the box is released then it will slide downwards on the slope because there is more mass in m1
Sorry, but that's the wrong reason … "more mass" doesn't clinch it … what matter is the equation your professor wrote down for you …
C. …
-m1*g*sin[tex]\theta[/tex]+T=m1(-a)
and
m2*g*T=m2(a)
(and btw, this is https://www.physicsforums.com/library.php?do=view_item&itemid=26", not third)

These two equations are the Ftotal = ma equations for m1 and m2 separately

(you have to do them separately) …

the first one is of the components in the direction of the slope, and the second is for the vertical components …

a is the same in both equations because the string has fixed length, so if m1 goes distance x up the slope, m2 goes distance vertically down …

so i] can you prove those two equations are correct?

ii] eliminate T, and find a :smile:
 
Last edited by a moderator:

Related Threads for: Newton's Third Law - Using pulleys and slopes

  • Last Post
Replies
6
Views
3K
  • Last Post
Replies
8
Views
38K
  • Last Post
Replies
1
Views
2K
Replies
1
Views
2K
Replies
1
Views
5K
Replies
21
Views
4K
Replies
15
Views
2K
Replies
1
Views
578
Top