No charge of particle in Schrodinger Equation

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Why does charge of a particle not appear in Schrodinger Equation even though mass appears?

Chapter 5
Q No. 9
Quantum Physics of Atoms Molecules Solids Nuclei and Particles - Robert Resnick, Robert Eisberg
 
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For the same reason that charge does not appear in the Newton Equation

m\mathbf{a}=\mathbf{F}
 
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arkajad said:
For the same reason that charge does not appear in the Newton Equation

m\mathbf{a}=\mathbf{F}

If possible kindly elaborate.
Thank You
 
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Well, there is no charge in Newton's equation, why there should be charge in Schrodinger's equation? The charge may appear in Newton's equation when you specify the force. It may appear in the Schrodinger equation when you specify the Hamiltonian.
 
arkajad said:
Well, there is no charge in Newton's equation, why there should be charge in Schrodinger's equation? The charge may appear in Newton's equation when you specify the force. It may appear in the Schrodinger equation when you specify the Hamiltonian.

Got it!
Thanks.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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