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cybhunter
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Homework Statement
five branches
left most branch: 50 Volt source
second left most: 10 ohm resistor
shared branch between the second left most branch and center: 10 ohms (Voltage drop from left to right= V delta)
center branch: 30 ohm resistor
between center and second right most: dependant voltage source (V delta/ 5)
second right most branch: 39 ohms
right most branch: 78 ohms
the second and right most branch have an unknown voltage 'vo'
find the vo voltage
Homework Equations
due to KCL, the current entering the voltage dependent source must equal the current leaving the dependent source:
vo=v2-(V delta/5) and v delta= 50 volts - v2
equating the currents:
(v2-50 Volts)/(10 ohms) +(v2)/(30 ohms) =(v2-(50 volts -v2)/5)/(39 ohms) + (v2-(50 volts -v2)/5)/(78 ohms)
rearranging the equation to equate to zero amperes:
(v2-50 Volts)/(10 ohms) +(v2)/(30 ohms) -(v2-(50 volts -v2)/5)/(39 ohms) - (v2-(50 volts -v2)/5)/(78 ohms)= 0 Amperes
using a Ti-89 to slove this (using the above equation as 'n1' and the output as 'v2')
solve(n1,{v2}) results in v2 being equal to 900/17 volts (~52.9412 Volts) meaning a V delta value of -2.9412 volts.
Checking the currents, the left side of the dependent source (not including the current across the 10 ohm resistor) is equal to 2.0589 Amperes, and the right side is equal to 2.0583 Amperes. Considering the ugly numbers I ended up mentioning it to my professor and he note that since it is a textbook example, the numbers should be integers and that the answer I got is wrong.
The Attempt at a Solution
(see attached)
Considering that the currents are very very close, I can assume to an extant that I am setting up the equations properly. What am I missing though?