Normal vector in surface integral of vector field

foo9008
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Homework Statement


when the normal vector n is oriented upward , why the dz/dx and dz/dy is negative ? shouldn't the k = positive , while the dz/dx and dz/dy is also positive?

Homework Equations

The Attempt at a Solution


is the author wrong ? [/B]
 

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Try a few examples and you'll see.
Remember when vectors are perpendicular
and when lines are perpendicular
 
BvU said:
Try a few examples and you'll see.
Remember when vectors are perpendicular
and when lines are perpendicular
Can you give some example?
 
z = x
 
BvU said:
z = x
i still don't understand what do you mean, can you explain further?
 
The surface ##\sigma## is defined by ##\phi(x,y,z)=0## where ##\phi(x,y,z)=z-f(x,y)##, and the normal is the gradient of ##\phi(x,y,z)##. What do you get when you calculate that?
 
vela said:
The surface ##\sigma## is defined by ##\phi(x,y,z)=0## where ##\phi(x,y,z)=z-f(x,y)##, and the normal is the gradient of ##\phi(x,y,z)##. What do you get when you calculate that?
why it will become like this ?
 
Why don't you simply fill it in and see ? Asking 'why' forever doesn't make sense. Make a sketch for the simplest case if 4.5.1 is too complicated.
 
foo9008 said:
why it will become like this ?
I'm sure this is covered in your textbook.
 
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