Normalize function - quantum chemistry

kanciara
Messages
1
Reaction score
0
Homework Statement
Normalize function f(r) = Nexp{-alpha*r}
Where alpha is positive const and r is a vector
Relevant Equations
f(r)=N*exp{-alpha*r}
Normalize function f(r) = Nexp{-alpha*r}
Where alpha is positive const and r is a vector

I was just wondering if the fact that we have a vector value in our equation changes anything about the solution
 
Physics news on Phys.org
kanciara said:
Homework Statement:: Normalize function f(r) = Nexp{-alpha*r}
Where alpha is positive const and r is a vector
Relevant Equations:: f(r)=N*exp{-alpha*r}

Normalize function f(r) = Nexp{-alpha*r}
Where alpha is positive const and r is a vector

I was just wondering if the fact that we have a vector value in our equation changes anything about the solution
Why do you think ##r## is a vector? Make sure you're not confusing vector ##\vec r## with its magnitude ##r##.
 
kanciara said:
Homework Statement:: Normalize function f(r) = Nexp{-alpha*r}
Where alpha is positive const and r is a vector
Relevant Equations:: f(r)=N*exp{-alpha*r}

Normalize function f(r) = Nexp{-alpha*r}
Where alpha is positive const and r is a vector

I was just wondering if the fact that we have a vector value in our equation changes anything about the solution
The argument inside the exponential needs to be a scalar, so it would have to be something like ## \alpha \cdot \textbf{r}##. It should be clear by context. I've seen ##\textbf{k} \cdot \textbf{x}## in a wavefunction but never written with a radial variable.

If it is a scalar product then you will have something like
##\int N e^{ \alpha _r r + \alpha _{ \theta } \theta + \alpha _{ \phi } \phi }## (or some such) which you should be able to separate out and integrate individually.

-Dan
 
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
It's given a gas of particles all identical which has T fixed and spin S. Let's ##g(\epsilon)## the density of orbital states and ##g(\epsilon) = g_0## for ##\forall \epsilon \in [\epsilon_0, \epsilon_1]##, zero otherwise. How to compute the number of accessible quantum states of one particle? This is my attempt, and I suspect that is not good. Let S=0 and then bosons in a system. Simply, if we have the density of orbitals we have to integrate ##g(\epsilon)## and we have...
Back
Top