Norton and Thevenin equivalents disagreement?

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SUMMARY

The discussion centers on the discrepancies between Norton and Thevenin equivalents when calculating the short-circuit current (Isc) between points c and d. The calculated Norton equivalent is 0.5mA, while the Thevenin equivalent yields 2mA. The confusion arises from mislabeling the voltage source Vx, which is incorrectly identified instead of the correct reference voltage VCD for the controlled voltage source in the third diagram. This misinterpretation leads to different results in the calculations.

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When I solve for Isc through a and b using Norton and Thevenin equivalents between c and d I get different results. Why is that?

Norton =0.5mA
Thevenin =2mA
 
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In the third diagram, the source you've labelled as Vx is not the same as VCD. It's VCD which is the reference voltage for the controlled voltage source.
 
gneill said:
In the third diagram, the source you've labelled as Vx is not the same as VCD. It's VCD which is the reference voltage for the controlled voltage source.

Thank you so much! So that's where I went wrong...
 

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