Not sure how to do this angular momentum, torque?

In summary, the conversation discusses the torque and angular momentum of two different particles in motion. The first particle experiences a force of 5x - 4y-6z (in N) and the second particle has a velocity of 4x +6y -5z (in m/s). To calculate the torque and angular momentum, the cross-product r x F or r x mV must be used.
  • #1
Raylyn
1
0
1. A particle at r = 2x +y + 3z (in m) is acted upon by a force F= 5x - 4y-6z (in N). What is the torque on this object (in Nm)?

2. A 3 kg particle at r = 1x + 2y - 3z (in m) has a velocity v +4x +6y -5z (in m/s). What is the angular momentum of this object (in kg m^2/s)?
 
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  • #2
Welcome to PF!

Raylyn said:
1. A particle at r = 2x +y + 3z (in m) is acted upon by a force F= 5x - 4y-6z (in N). What is the torque on this object (in Nm)?

2. A 3 kg particle at r = 1x + 2y - 3z (in m) has a velocity v +4x +6y -5z (in m/s). What is the angular momentum of this object (in kg m^2/s)?

Hi Raylyn! Welcome to PF! :smile:

Your questions don't make sense … a torque or an angular momentum has to be measured about a particular point, and your questions don't mention one.

If it means what is the torque or angular momentum about the origin (0,0,0), then you must use the cross-product r x F or r x mV. :smile:
 
  • #3


I would suggest using the fundamental equations for torque and angular momentum to solve these problems. For the first problem, the torque can be calculated by taking the cross product of the position vector (r) and the force vector (F). This will give us a vector quantity, which can be converted to a scalar by taking its magnitude. The final answer will be in Newton-meters (Nm).

For the second problem, the angular momentum can be calculated by taking the cross product of the position vector (r) and the velocity vector (v). Again, this will give us a vector quantity, which can be converted to a scalar by taking its magnitude. The final answer will be in kilogram meters squared per second (kg m^2/s).

It is important to note that both torque and angular momentum are vector quantities, meaning they have both magnitude and direction. Therefore, it is important to pay attention to the direction of the vectors used in the calculations and make sure they are consistent throughout. Additionally, make sure to use the correct units for each quantity in order to get the correct final answer. I hope this helps guide you in solving these problems.
 

Related to Not sure how to do this angular momentum, torque?

1. What is angular momentum and torque?

Angular momentum is a measure of the rotational motion of an object, taking into account its mass and velocity. Torque, on the other hand, is the force that causes an object to rotate around an axis.

2. How do you calculate angular momentum and torque?

To calculate angular momentum, you multiply the moment of inertia (a measure of an object's resistance to rotation) by the angular velocity (the rate of change of an object's angular position). Torque can be calculated by multiplying the force applied to an object by the distance from the axis of rotation.

3. What is the relationship between angular momentum and torque?

Angular momentum and torque are directly related, as torque is the force that causes changes in angular momentum. The greater the torque applied to an object, the greater its change in angular momentum will be.

4. What are some real-world examples of angular momentum and torque?

Some examples of angular momentum and torque in action include a spinning top, a rotating planet, and a turning wheel. In each of these cases, there is a force applied to the object that causes it to rotate around an axis.

5. How does angular momentum and torque relate to conservation of energy?

Angular momentum and torque are both important concepts in the conservation of energy. In a closed system, the total angular momentum and torque will remain constant, meaning that any changes in one will be balanced by changes in the other. This principle is known as the law of conservation of angular momentum.

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