This one's not too hard...A 1.30kg toaster is not plugged in. The coeffficient of static friction b/t the toaster and horizontal countertop is .350. To make the toaster start moving, you carelessly pull on its electric cord. a) for the cord tension to be as small as possible, you should pull at what angle above the horizontal? b) With this angle, how large must the tension be?
Ok so I have Tcos(theta)-fs-mg
fs=force of static friction fs=uk*n = (.350)(1.30kg)(9.80m/s^2)=4.459 N
mg=12.74 N
Tcos(theta)-4.459N-12.74N ......my question is, Im not sure how to solve tension or angle without having one or the other????
Ok so I have Tcos(theta)-fs-mg
fs=force of static friction fs=uk*n = (.350)(1.30kg)(9.80m/s^2)=4.459 N
mg=12.74 N
Tcos(theta)-4.459N-12.74N ......my question is, Im not sure how to solve tension or angle without having one or the other????