NPN question typo or my misunderstanding

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The discussion revolves around confusion regarding the formula for base current (Ib) in NPN transistors. The original source states Ib = (VE + 0.6V)/R1, which raises questions about its accuracy. The user believes the correct formula should be Ib = (Vcc - 0.6V)/R1, as the emitter is grounded and the transistor is confirmed to be on. There is also mention of minimal voltage drop across the collector side light bulb, suggesting the transistor operates in the linear region. The inquiry seeks clarification on whether the discrepancy is due to a typo or a misunderstanding of the concepts.
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Ok so I'm reviewing npn transistors and here is what I am looking at

http://postimage.org/image/sdywponvv/

Now the book I bought says Ib = (VE + 0.6V)/R1
I have no idea why it would be that

Isn't it suppose to be

(Vcc -0.6V)/R1 for Ib

The transistor is definitely on as emitter is grounded
and it says that there isn't too big of a voltage drop over the collector side light bulb so it should be in linear region

So Typo or am I misunderstanding something
 
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