Object moving in equilateral triangle - magnitude of acceleration

AI Thread Summary
An object moves with a constant speed of 22.3 m/s around an equilateral triangle, completing the path in 12.69 seconds. The average acceleration vector's magnitude is calculated using vector components and relevant equations. The solution involves breaking down the motion into x and y components. The final calculated average acceleration is 3.04 m/s². This demonstrates the relationship between constant speed and changing direction in circular motion.
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Homework Statement


An object moves around a equilateral triangle with a constant speed (magnitude of velocity is constant) of 22.3 m/s. If it moves from the starting to ending point (as shown below) in a time of 12.69 seconds, what is the magnitude of the average acceleration vector in m/s2?



Homework Equations



V\DeltaV= (rFx-rix/delta(t)) - (rfy-riy\delta (t))


The Attempt at a Solution

 
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Break the vector into x and y components then use the equation:
(delta)y=v0t-(1/2)gt^2
 


Thanks! i figured out the answer.. its 3.04
 
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