Object sliding down inclined plane

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An object sliding down a 30-degree inclined plane with an initial speed of 5 m/s needs to account for the vertical height when calculating final speed. The correct height (h) is determined using the formula h = 4sin(30), which gives the vertical distance moved. The energy conservation equation Kinitial + Uinitial = Kfinal + Ufinal is applied correctly, but the height must be accurately defined. After correcting for height, the final speed can be recalculated. This approach ensures accurate results in physics problems involving inclined planes.
akatsafa
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An object slides down an inclined plane of angle 30 degrees and of incline length 4m. If the initial speed of the object is 5m/s directed down the incline, what is the speed at the bottom? Neglect friction.

I used Kinitial+Uinitial=Kfinal+Ufinal. I got 2gh+5^2=v^2, but when I solve for v, I get 10.17m/s. What am I doing wrong?
 
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akatsafa said:
I used Kinitial+Uinitial=Kfinal+Ufinal. I got 2gh+5^2=v^2, but when I solve for v, I get 10.17m/s. What am I doing wrong?
What did you use for h? h must be the vertical distance the object moves, not the distance along the incline.
 
Should I use 4sin30 as my height?
 
akatsafa said:
Should I use 4sin30 as my height?
Yes. That's the height.
 

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