Ohms law for concentric spherical shells

zezima1
Messages
119
Reaction score
0
Look at the attached problem with solutions. I don't understand what the author means in c) when he says that succesive shells contribute less and less because the cross sectional area grows proportional to r2. The flux through a closed surface is always the same (Gauss' law). Rather the reason why the b becomes negligible is in my opionion that you are very far away from the shell. Can anyone explain what the author means by this "succesive shells contribute less and less"?
 

Attachments

  • concentricshells.jpg
    concentricshells.jpg
    25.4 KB · Views: 691
Physics news on Phys.org
There is an elementary formula for the resistance, dR, of a thin slab of material of thickness dx and cross-sectional area A: dR = \frac{dx}{σA}.

See if you can apply this to a thin spherical shell of radius r and thickness dx = dr.

How does the resistance of the shell depend on r? What happens as r goes to ∞?

If you integrate the expression for dR from r = a to r = b you should get the formula for the total resistance of the material that lies between the sphere of radius r = a and the sphere of radius r = b.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top