# Ohm's law problems. help

nutzweb
ohm's law problems. help....

Research Work:

What is an ideal ammeter and an ideal voltmeter? Why are voltmeters connected in parallel? Why are ammeters connected in series?

Problems:

answer any number that you know. thanks so much. i just neede it badly...

1.What is the potential difference across a 220-Ω resistor when a current of 3.50 A flows through it?

2.A 40-W electric lamp draws a current of 0.33 A when operated with a potential difference of 120 V. What is the resistance of the lamp?

3.A three-cell flashlight draws a current of 0.60 A. What is the operating resistance of the light bulb if each cell provides a potential of 1.0 V when delivering this current?

4.The current through an electronic device is measured for several different voltages applied across the device. When the potential difference is 0 V, 0.50 V, and 0.75 V, the current is 0 A, 0.010 A, and 0.015 A, respectively. Does the device obey Ohm’s Law?

Gold Member
An ideal ammeter would be one that could measure the current in a circuit without changing it. It would have no resistance. An ideal voltmeter would be one that could measure the voltage difference between two points in a circuit without changing that voltage. It would have an infinite resistance.

Voltmeters measure the votage difference between two points in a circuit. If you connrcted one in series with a circuit, think about what you would be measuring. That should explain why they are generally connected in parallel.

Ammeters measure the current flowing through them and have very little resistance. Think about what would happen if you connected one in parallel. Since it would alter the current flowing in the rest of the circuit, what you would be measuring wouldn't be very meaningful.

1. Try Ohm's law: V=IR
2. Use the formula for the power, P, to solve for R: [itex]P=I^2R[/tex] (The problem gives extra information, but is not inconsistant with itself.)
3. Presumably the cells are connected in parallel and the total voltage is the sum of the ndividual voltages. From there it's just Ohm's law again.
4. Basically, just solve for R in Ohm's law for each voltage (other than 0, as this will be indeterminant). Is R the same in each case?

Gold Member
1/ V= 220*3.50 =770
2/ R = 120/0.33 =363.6
3/ R = (1+1+1)/0.6 =5
4/ V= 0*R, V=0.5=0.010*R => R =50, V=0.75=0.015*R => R=50 So YES.