One More Accelerated Parallel Force

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To determine the parallel force needed to accelerate a 5.0 kg object at 12 m/s² on a horizontal surface, the normal force is calculated as 49 N. The maximum static friction force is 7.35 N, but since the object is moving, the kinetic friction coefficient (uk = 0.07) is used. The kinetic friction force is found by multiplying the normal force by the kinetic friction coefficient, resulting in approximately 3.43 N. The total force required for acceleration combines the frictional force and the force from F=ma, leading to a total of 63.4 N, confirming option D as the correct answer. The discussion emphasizes the importance of using the correct friction coefficient for moving objects.
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"For a 5.0 kg object on a horizontal surface that has a coefiicient of static friciton where us = 0.15 and a coefficient of kinetic friction where uk = 0.07, what is the parallel force necessary to accelerate the object at 12 m/s^2."

a) 53.6 N
b) 56.6 N
c) 60.0 N
d) 63.4 N
e) 67.4 N

I found that the normal force (FN) is 49 N. The max force is 7.35 N. However, I don't know how I would go about finding a force needed to accelerate an object. ...help...
 
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Which mu should you use if the object is moving? The force in F=ma will be the combination of the frictional force and the force required to accelerate the mass...
 
by using F=ma, 5*12, I get 60. For the uk force, I multiplied 49*.07. then uk force + force = 63.4, answer D
 
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