Engineering Op-amp circuit analysis using a transfer function

AI Thread Summary
The discussion focuses on analyzing op-amp circuit transfer functions W(s) and Wk(s), with an emphasis on correcting Wk(s) to achieve the desired frequency response. The user expresses confusion regarding the unexpected gain in Wk(s) after the corner frequency, which deviates from the standard W(s) response. Suggestions include canceling an identical pole and zero at s = -10 and adjusting the high-frequency gain to 1.0. The user acknowledges a misunderstanding about the task and seeks clarification on the correct implementation of Wk(s). Ultimately, the task is completed after receiving guidance on eliminating one pole and one zero to align the Bode plot with expectations.
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Homework Statement


I have got transfer functions W(s) and Wk(s), where Wk(s) is correction transfer function.
mze1n52gh4shducqu6ss.png

So I calculate W(s) and Wk(s) in series.
Magnitude graph before correction:
325tqtj68jjtfve4xax4.png

Magnitude graph after correction:
w0u4vt6j0l6dx7gy0zb.png


The task is to make whole circuit and simulate it.

Homework Equations



The Attempt at a Solution


First of all, I tried to make it by parts:
xhzrr15rampgus2k6yn.png

e9n83phl8ipa03rslcp.png

d8kevj1wadhpmwwf5b8.png


What about 70/s?
And am I on the right way with otherones?
 
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first, you should cancel the identical pole & zero at s = -10.
then, the second ckt is incorrect. what is the high freq. gain of (0.01s+1)/(0.017s+1)? What components determine the high-freq. gain?
finally, suppose you have an inverter with gain = -Zf/Zi. Equate Zf/Zi to k/s to find your Zi and Zf components.
.
 
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It seems to me, I had a missunderstanding about the task. And there is mistake in the correction TF Wk(s), I guess.
I simulated W(s) - red colour, Wk(s) -green colour, W(s)*Wk(s) - blue colour.
Bode plot:

http://www.bildites.lv/images/5ltl503z567e84sgk3pk.png

The problem is gain of Wk(s) TF. After corner frequency W1, I expect the graphic like it is standart W(s) (red), but it isn't, because there is unexpected gain in Wk(s).

Here are calculations, how I get Wk(s) and simulation:
3iecivaigdiobzfrpbfp.png


And the problem is not because 1/60 = 0.0166666.. = ~ 0.017
There's something wrong with gain. What can be reason for wrong result?
 
I see nothing wrong with this. If Wk(s) = what you say, then your implementation is correct. The low freq. gain is 1.0, the high freq. gain is 1.47 and the time constants all check out.

What about your pole at the origin?
 
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I calculated Wk(s) by myself, it wasn't given.
I have got standart W(s) and I have to implement Wk(s) to get graphic like this (red is correction):
ifvdxt4h1auq0tf5kz13.png

on5jgaoq27ucoh6ewnju.png


But in the bode plot (in my previous post), after last corner frequency the new graphic isn't like the standart W(s), because there is this small gain. Maybe I don't understand something about it, but it suggests that there's mistake in my Wk(s) TF, because the high frequency gain is 1.47, but I want the gain to be 1.0 to get the same graphic after that corner frequency. What could be wrong there with Wk(s) in this case?

Corner frequencies: 1, 4, 10 60 rad/s were suggested by teacher.
 
Well, you're confusing me a lot.

OK, if you want to correct per your latest frequency response (the bottom graph), you need to eliminate one pole and one zero. So figure out what your W_k(s) should be to cancel those. Your Bode plot (red) tells you what to do.
 
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Thanks for the hint. Task already done.
 
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