Organic chem: draw this in line angle structure

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Discussion Overview

The discussion revolves around converting a condensed organic chemical formula into its line angle structure. Participants explore the interpretation of specific segments of the formula, particularly focusing on the structure represented by the CC(CH2)3 portion.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant expresses confusion regarding the CC(CH2)3 part of the formula, initially considering the possibility of a cyclobutanyl group to represent three methyl groups.
  • Another participant clarifies that (CH2)3 represents three -CH2- groups in a linear arrangement.
  • Some participants suggest that the CC could be interpreted as a double bond (C=C), but this is later corrected.
  • A later reply indicates that the correct interpretation of CC is actually a triple bond (C≡C), although this is met with some uncertainty.
  • One participant acknowledges their earlier mistake regarding the bond type and expresses gratitude for the assistance received.
  • Another participant confirms the correctness of the line angle structure drawn by the first participant.

Areas of Agreement / Disagreement

There is no clear consensus on the interpretation of the CC segment, with some participants initially suggesting it could be a double bond while others clarify it is not. The discussion reflects uncertainty and competing interpretations regarding the structure.

Contextual Notes

Participants express confusion over the representation of certain groups in the condensed formula, indicating potential limitations in understanding the structural implications of the notation used.

alphaj
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Homework Statement


Draw this formula in line angle structure. CH3CH2OC(O)CH2CC(CH2)3CH(CN)CHO.

Homework Equations


None.

The Attempt at a Solution


I'm confused with the CC(CH2)3 part of the condensed formula. I knew I got it wrong the first time I drew it because I couldn't just tag three methyl groups to carbon 7. The only way I think I can do that is by adding a cyclobutanyl group! But, I'm afraid that might be misrepresenting the given formula. I think a cyclobutanyl group included would have the condensed formula written as CH3CH2OC(O)CH2C(C(CH2)3)CH(CN)CHO.
upload_2017-9-24_16-37-58.png
 
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(CH2)3 is just three -CH2- groups in line.
 
if memory serves me correctly, the CC is actually C=C and the (CH_2)_3 is
CH_2CH_2CH_2
 
Dr Transport said:
the CC is actually C=C

Close, but no, it is not a double bond.
 
Borek said:
Close, but no, it is not a double bond.
memory failed me...
 
upload_2017-9-24_20-59-1.png

Thanks for your help! I think I got it now!
 
alphaj said:
CH3CH2OC(O)CH2CC(CH2)3CH(CN)CHO

Yes, looks like you are right.

705e429997f8df570d08.png


@Dr Transport - you were close, it was just C\equiv C, not C=C.
 

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