Parallel Plate Capacitor True or False

AI Thread Summary
The discussion focuses on the correct and incorrect statements regarding the behavior of isolated parallel plate capacitors. Key points include that doubling the distance between plates increases stored energy, while inserting a dielectric decreases energy and increases capacitance and charge. It is clarified that increasing the distance does not decrease the electric field strength, and halving the distance does not keep charge constant. Participants are encouraged to review the relevant equations for capacitance and electric potential energy to better understand these concepts. Understanding these principles is essential for accurately answering questions related to parallel plate capacitors.
ysk1
Messages
32
Reaction score
1
I keep getting the questions wrong. I'm so frustrated. I'd appreciate it if anyone can tell me what's wrong.

Which statements are correct/incorrect for two oppositely charged, isolated parallel plates (Isolated means that the charge stays constant ):
(C=capacitance, U=stored energy, +Q and -Q = charge on the plates).


1. When the distance is doubled, U increases. T
2. Inserting a dielectric decreases U. F
3. Increasing the distance, decreases the E field. F
4. When the distance is halved, Q stays the same. F
5. Inserting a dielectric increases C. T
6. Inserting a dielectric increases Q. T
7. When the distance is doubled, C increases. F
 
Physics news on Phys.org
It will be of help to you to write down:

1) the expression for finding C for a parallel-plate capacitor

and

2) the expression for the electric potential energy U in a capacitor in terms of C and Q (the versions involving V will complicate things) .

#5 is correct. Re-read the condition for the charge on this capacitor to understand why you got #4 and #6 wrong. The equations I suggested will help you figure out why the others are incorrect. (Oh, for #3, how do the field for a sheet of uniform charge density depend on distance from it?)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top