- #1
elitespart
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- 0
[tex]\int e^{ax}cosbx[/tex]
This one is driving me insane.
So I used e^ax as u and cosbx dx as dv. And then I did it again using e^ax as u and sinbx as dv which left me with [tex]\int e^{ax}cosbx = \frac{1}{b}e^{ax}sinbx + \frac{a}{b^{2}}e^{ax}cosbx - \frac{a^{2}}{b^{2}}\int e^{ax}cosbxdx[/tex]
I have no ideas if this is right and no clue what do after if it is. Thanks.
This one is driving me insane.
So I used e^ax as u and cosbx dx as dv. And then I did it again using e^ax as u and sinbx as dv which left me with [tex]\int e^{ax}cosbx = \frac{1}{b}e^{ax}sinbx + \frac{a}{b^{2}}e^{ax}cosbx - \frac{a^{2}}{b^{2}}\int e^{ax}cosbxdx[/tex]
I have no ideas if this is right and no clue what do after if it is. Thanks.