Particle moving along a parabola

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The discussion revolves around a particle moving along a parabola with the displacement equation s = 0.5t². In Part I, the user seeks confirmation on their calculations regarding the velocity and acceleration components, with some answers being validated while others require correction. Specifically, the user mistakenly used displacement instead of velocity for calculations, leading to inaccuracies in determining the y-component of velocity and acceleration. In Part II, there is confusion about whether the particle's speed can be constant given the provided equations, as the speed appears to vary with time. Overall, clarification on the relationship between the coordinates and the equations is needed for accurate analysis.
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Can someone please check that everything I have done so far is correct?

A particle movies along a parabola with the displacement equation s = 0.5t2.
(a graph is shown)

::::Part I::::

Suppose x-component is s = Ct
i) indicate direction of velocity vector and acceleration at point R (arbitrary point on graph)
ii) Determine y-component of particles velocity
iii) Determine y-component of particles acceleration

Answers:

i) I suppose the velocity vector would be tangential to the graph and the acceleration vector would be parallel with the y-axis?
ii) since V = √(Vx2 + Vy2), and V = t, I found that the y - component is √(t2-C2t2).
iii) Since the acceleration is constant, is the y-component simply C?


:::Part II::::


Suppose instead that the x-component of the velocity is given by \frac{C}{\sqrt{1 + t^{2}}}

i) Show that the particle's speed is constant

I am unsure how to attempt Part II.

If you are able to answer or confirm my answers to any part of this question, thank you very much!
 
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Some help would be greatly appreciated!
 
We need some explanation. What is s? I do not see the graph.

ehild
 
For part (i) - you are right,
For part (ii) you have used s_x instead of V_x to determine V_y
For part (iii) - yes, the acceleration is constant, but it is not equal to C; but maybe try determining the total acceleration, and the acceleration in the x direction instead of differentiating...
- if you typo'd s=Ct; and it's actually V_x=Ct, then your answer to part (i) is wrong, part (ii) is right and you still need to determine part (iii) - it's a constant still, but not C

For part (II)
there isn't enoguh information - is the total motion of the particle still given by s=.5t^2?
Because in that case, the particles speed can't be constant - it's speed is, as you said, is equal to t, which is a variable.
Was there any other information?
 
s=0.5t^2 is a scalar equation. If s is displacement, the particle moves along a straight line, not along a parabola. If a particle moves along a parabola, you need to give the relation between its coordinates. Can you show the original text of the problem?

ehild
 
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