Percentage Change in Sound Intensity - Help

AI Thread Summary
An intensity level change of +2.00 dB corresponds to a percentage change in intensity of approximately 58.5%. The calculation involves using the formula B = 10 log (I/Io), leading to I/Io = 1.585 when solving for intensity. Assuming Io = 1, the percentage difference is calculated as 100(1.585-1.0). The solution has been confirmed as correct by multiple participants in the discussion. The calculations and reasoning presented are accurate and validated.
dvolpe
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Homework Statement


An intensity level change of +2.00 dB corresponds to what percentage change in intensity!


Homework Equations



B = dB = 10 log (I/Io)

The Attempt at a Solution


2.00 dB = 10 log (I/Io)
0.2 = log (I/Io)
I/Io = 10e0.2 = 1.585

Assuming Io = 1, then percentage difference = 100(1.585-1.0) = 58.5%.

Is this correct? Please help asap.
 
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This is correct per webassign
 
dvolpe said:
This is correct per webassign
Yup, looks good to me too.
 
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