Period of Pendulum in Accel. Elevator

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The discussion focuses on calculating the period of a simple pendulum with a length of 5.00m in an elevator under different accelerations. For upward acceleration at 5.00 m/s², the modified period formula is τ = 2π√(L/(g + a₁)), while for downward acceleration, it is τ = 2π√(L/(g - a₁)). The participants clarify that the period is adjusted based on the elevator's acceleration affecting the effective gravitational force. There is also a mention of issues with LaTeX formatting in the discussion. Overall, the thread emphasizes the relationship between pendulum period and acceleration in varying conditions.
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A simple pendulum is 5.00m long. (a) What is the period of small oscilliations for this pendulum if it is located in an elevator accelerating upward at 5.00 m/s^2? (b) what is its period if the elevator is accelerating downward at 5.00 m/s^2?:confused:
 
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What id the period for an arbitrary acceleration g?

-Dale
 
the pendulum's period is just the normal period of the pendulum with
g modified by the different accelerations
i.e.
\tau = 2 \pi \sqrt{\frac{L}{g}}
goes to
\tau = 2\pi \sqrt{\frac{L}{g+a_1}}
and
\tau = 2\pi \sqrt{\frac{L}{g-a_1}}
 
Last edited:
hmm
why didn't the latex get processed?

nm does not equal [ tex ]
 
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Thank you

Thank you for helping me, can i add you as a buddy?:blushing:
 
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