Period of pendulum moved to Jupiter's moon Io

AI Thread Summary
The discussion revolves around calculating the oscillation period of a pendulum clock on Jupiter's moon Io, given its radius and mass. The initial oscillation time on Earth is 1 second, and participants are trying to derive the formula for the period on Io using gravitational constants. There is confusion regarding the variables used, particularly the gravitational acceleration (g) on Io compared to Earth, and the length of the pendulum. The conversation emphasizes the need for clarity in the equations and the correct application of gravitational formulas. Ultimately, participants are encouraged to derive the necessary equations to complete the calculation.
robax25
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Homework Statement



you are taking your pendulum clock with you to a visit of the Jupiter moon Io(radious 3643.2Km, mass 8.94X10^22 kg. calculate the duration of a full Oscillation. On the surface this oscillation time was 1s

Homework Equations


T=2*π√l/g[/B]

The Attempt at a Solution


T1/T2=√(g2/g1)
 
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robax25 said:
T1/T2=√(D1/D2)
=√((Gmr^2/9,81)/D1)
What are D1 and D2, and how do you get the second equation from the first?
 
D means g . If you divideT1/T2=2*π√l1/g / 2*π√l2/g. the you get the equation
 
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Moderator's note: I've changed the title of this thread to be more specific and descriptive of the actual problem.
 
robax25 said:
D means g . If you divideT1/T2=2*π√l1/g / 2*π√l2/g. the you get the equation
What is l (lower-case L)? What is g?
 
NascentOxygen said:
What is l (lower-case L)? What is g?
L is the length of the pendulum and g is the Gravitational costant
 
It's one pendulum clock that gets transported to Io, so how can there be two different pendulum lengths?

Usually G is the gravitational constant symbol. What numerical value are you using for lower-case g here?
 
NascentOxygen said:
It's one pendulum clock that gets transported to Io, so how can there be two different pendulum lengths?

Usually G is the gravitational constant symbol. What numerical value are you using for lower-case g here?
yes, G differs from Earth to Jupiter's moon Io. For earth, it is 9.81m/s^2... and Io moon is not mentioned. so we need to use gravitational formula to solve it
 
robax25 said:

Homework Statement



you are taking your pendulum clock with you to a visit of the Jupiter moon Io(radious 3643.2Km, mass 8.94X10^22 kg. calculate the duration of a full Oscillation. On the Earth's surface this oscillation time was 1s
I have clarified the problem statement here, to present it as I believe would have been intended.
 
  • #10
NascentOxygen said:
I have clarified the problem statement here, to present it as I believe would have been intended.
i mean that.
 
  • #11
So you have a final equation for TIo that involves the mass of Io?
 
  • #12
NascentOxygen said:
So you have a final equation for TIo that involves the mass of Io?
No, I do not have the equation. I am confused.
 
  • #13
Where's the confusion?
 
  • #14
NascentOxygen said:
Where's the confusion?

The Attempt at a Solution


T1/T2=√(g2/g1)

How I can go ahead?
 
  • #15
You'll need to show the working you followed in deriving that equation, by starting with something that you know to be right.
 
  • #16
NascentOxygen said:
You'll need to show the working you followed in deriving that equation, by starting with something that you know to be right.
If you divideT1/T2=2*π√l/g1 / 2*π√l/g2. the you get the equation l= radious of the Pendulum and g is the gravitational constant.
 
  • #17
Okay, so you need formulae or equations for g1 and g2 . What formula can you use for this?
 
  • #18
g=GM/r^2
 
  • #19
Go ahead and see whether you can now finish this.
 
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