- #1

- 42

- 2

## Homework Statement

Assume all oscillators are frictionless.

a) A pendulum consists of point mass Mo swinging on a massless string of length Lo, with period To = 9.42 s on the surface of the Earth (at RE, the radius of the Earth). Find T1, the period of the same pendulum if it swings on a horizontal platform of height H = 2.96RE (stationary, not orbiting) above the Earth's surface.

## Homework Equations

T = 2∏√(L/g) , g = GM/R

^{2}, Radius of earth = 6.37e6m, mass of earth = 5.98e24kg

## The Attempt at a Solution

g(T/2∏)

^{2}= L

9.81m/s

^{2}√(9.42s/2∏)

^{2}= 22.05012604m

g = GM/R

^{2}

(6.67e-11 * 5.98e24kg)/(2.96 * 6.37e6)

^{2}= g1

3.98866e14/3.55518567e14 = 1.121927339m/s

^{2}= g1

T1 = 2∏√(L/g1)

T1 = 2∏√(22.05012604/1.121927339)

T1 = 27.85499219s

The answer i calculated is wrong, any help with figuring out why it's wrong would be greatly appreciated