Assume all oscillators are frictionless.
a) A pendulum consists of point mass Mo swinging on a massless string of length Lo, with period To = 9.42 s on the surface of the Earth (at RE, the radius of the Earth). Find T1, the period of the same pendulum if it swings on a horizontal platform of height H = 2.96RE (stationary, not orbiting) above the Earth's surface.
T = 2∏√(L/g) , g = GM/R2 , Radius of earth = 6.37e6m, mass of earth = 5.98e24kg
The Attempt at a Solution
g(T/2∏)2 = L
9.81m/s2√(9.42s/2∏)2 = 22.05012604m
g = GM/R2
(6.67e-11 * 5.98e24kg)/(2.96 * 6.37e6)2 = g1
3.98866e14/3.55518567e14 = 1.121927339m/s2 = g1
T1 = 2∏√(L/g1)
T1 = 2∏√(22.05012604/1.121927339)
T1 = 27.85499219s
The answer i calculated is wrong, any help with figuring out why it's wrong would be greatly appreciated