Period of Vibration of Torsion Pendulum

AI Thread Summary
To find the torsion constant (K) of a torsion pendulum, the period (T) and moment of inertia (I) are essential. Given T = 1.32s and I = 0.0383 kgm^2, the calculated value for K is 0.8678. The solution involves substituting these values into the appropriate formula. There was a mention of a calculator error affecting the initial attempt at the solution. Understanding algebra is crucial for correctly solving the equation.
Felicity Wang
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Homework Statement


Given the period (T) and the moment of inertia (I), find the Torsion constant (K)
T= 1.32s
I= 0.0383 kgm^2

Homework Equations


image05.png


The Attempt at a Solution


The answer is K=0.8678, I'm not really sure how to get the answer, but I think it has to do with the units.
 
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Felicity Wang said:

Homework Statement


Given the period (T) and the moment of inertia (I), find the Torsion constant (K)
T= 1.32s
I= 0.0383 kgm^2

Homework Equations


image05.png


The Attempt at a Solution


The answer is K=0.8678, I'm not really sure how to get the answer, but I think it has to do with the units.
That's a big equation! :-)

Are you at ease with algebra? You just need to plug in the values of T and I in the formula and then solve for K.
 
nrqed said:
That's a big equation! :-)

Are you at ease with algebra? You just need to plug in the values of T and I in the formula and then solve for K.
Haha just realized there was an error with my calculator. Thanks!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
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