Period, the Pendulum and Frequency

AI Thread Summary
Adjusting a pendulum's frequency from 10 Hz to 20 Hz results in its period changing from n seconds to n/2 seconds, as frequency and period are inversely related. A user expresses confusion over a calorimetry problem involving a piece of copper and water, initially calculating an incorrect final temperature of 255°C. The forum responses emphasize the importance of showing work for problem-solving and adhering to posting guidelines. Users are encouraged to ask separate questions in different threads for clarity. Overall, the discussion highlights the relationship between frequency and period while addressing a common misunderstanding in thermal equilibrium calculations.
alwysnforevr002
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If a pendulum is adjusted so that its frequency changes from 10 Hz to 20 Hz, its period will change from n seconds to what?
a. n/4 seconds.
b. n/2 seconds.
c. 2n seconds.
d. 4n seconds
 
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what are your thoughts so far?
 
Well i think they are inversly related therefore i think the answer should be n/2.
 
Yes frequency is 1/t so double frequency half the time.
 
Great! Thank You so much. If you have a moment I have another question.

A 0.10 kg piece of copper at an initial temperature of 95°C is dropped into 0.20 kg of water contained in a 0.28 kg aluminum calorimeter. The water and calorimeter are initially at 15°C. What is the final temperature of the system when it reaches equilibrium?

For this problem i can only find an equation that solves for the intial temperature. I tried to solve this equation and i got 255 degress C which i know has to be incorrect because if the piece of copper starts at 95 degrees celcius and is put in cooler water it is not going to get hotter but colder.
If you cant/do not wish to answer this question that is perfectly fine but thank you again for you reassurance on my last question!
 
alwys,

1. Try and post questions on different topics in different threads.

2. Read the forum posting guidelines (see my signature for the link). We can only help you if you show your effort first. We will not provide answers to multiple choice questions.

3. For this problem, it looks like you may have made a calculation/arithmetic arror. We can't tell you where the error is unless you show us the steps you took.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

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