- #1
spiff711
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Problem:
The pH of pure water at 37°C is 6.80. Calculate Kw,
pOH, and [OH-] at this temperature.
Work:
pH: 6.8
pOH = 14 -6.8 = 7.2
[OH]: 10-7.2 = 6.3 x 10-8 M
Kw= [H3O] [OH] = 1.5 x 10-7 x 6.3 x 10-8 = 1x10-14
Real answer:
pH:6.8
pOH:6.8
[OH]: 1.6x10-7
Kw: 2.5 x 10-14
What am I doing wrong? Any help would be greatly appreciated.
The pH of pure water at 37°C is 6.80. Calculate Kw,
pOH, and [OH-] at this temperature.
Work:
pH: 6.8
pOH = 14 -6.8 = 7.2
[OH]: 10-7.2 = 6.3 x 10-8 M
Kw= [H3O] [OH] = 1.5 x 10-7 x 6.3 x 10-8 = 1x10-14
Real answer:
pH:6.8
pOH:6.8
[OH]: 1.6x10-7
Kw: 2.5 x 10-14
What am I doing wrong? Any help would be greatly appreciated.