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mneox
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Phase Angle / Phase Question - Simple Harmonic Motion
If I were given a function of displacement for simple harmonic motion in the form of:
x = Acos([tex]\omega[/tex]t + [tex]\phi[/tex])
Would the phase angle, [tex]\phi[/tex], always be the same? Say if I derived the equations into forms for velocity and acceleration as well. The phase angle would not change.. is that correct?
Also, I am confused about what is the phase and what is the phase angle? My textbook lists the "phase angle" as [tex]\phi[/tex] and some other sources list "phase" as ([tex]\omega[/tex]t + [tex]\phi[/tex]). What's the difference between these??
x = Acos([tex]\omega[/tex]t + [tex]\phi[/tex])
v = -[tex]\omega[/tex]Acos([tex]\omega[/tex]t + [tex]\phi[/tex])
a = -[tex]\omega[/tex]2Acos([tex]\omega[/tex]t + [tex]\phi[/tex])
My belief is that it wouldn't change, but I want to be 100% sure.
Thanks for your clarification!
Homework Statement
If I were given a function of displacement for simple harmonic motion in the form of:
x = Acos([tex]\omega[/tex]t + [tex]\phi[/tex])
Would the phase angle, [tex]\phi[/tex], always be the same? Say if I derived the equations into forms for velocity and acceleration as well. The phase angle would not change.. is that correct?
Also, I am confused about what is the phase and what is the phase angle? My textbook lists the "phase angle" as [tex]\phi[/tex] and some other sources list "phase" as ([tex]\omega[/tex]t + [tex]\phi[/tex]). What's the difference between these??
Homework Equations
x = Acos([tex]\omega[/tex]t + [tex]\phi[/tex])
v = -[tex]\omega[/tex]Acos([tex]\omega[/tex]t + [tex]\phi[/tex])
a = -[tex]\omega[/tex]2Acos([tex]\omega[/tex]t + [tex]\phi[/tex])
The Attempt at a Solution
My belief is that it wouldn't change, but I want to be 100% sure.
Thanks for your clarification!
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