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Phase of Motion (SHM)

  1. Jan 11, 2012 #1
    1. The problem statement, all variables and given/known data

    The function x = (2.0 m) cos[(6π rad/s)t + π/2 rad] gives the simple harmonic motion of a body. Find the following values at t = 10.0 s.

    I am having trouble finding the phase of the motion, The book gives an answer of 190 rad, Im not sure how they got that

    2. Relevant equations

    V(t) = -12[itex]\pi[/itex]Sin(6[itex]\pi[/itex]t+([itex]\pi[/itex]/2))
    a(t) = -12[itex]\pi[/itex](6[itex]\pi[/itex])Cos(6[itex]\pi[/itex]t+([itex]\pi[/itex]/2))


    3. The attempt at a solution

    The displacement and acceleration are zero, but for some reason when i plug them into my calculator (it is set to radians) i keep getting answers other than zero, any suggestions?
     
  2. jcsd
  3. Jan 11, 2012 #2
    Just found out what i was missing, and feel like a complete fool, sorry to bother you all with this, Thank You
     
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