The function x = (2.0 m) cos[(6π rad/s)t + π/2 rad] gives the simple harmonic motion of a body. Find the following values at t = 10.0 s.
I am having trouble finding the phase of the motion, The book gives an answer of 190 rad, Im not sure how they got that
V(t) = -12[itex]\pi[/itex]Sin(6[itex]\pi[/itex]t+([itex]\pi[/itex]/2))
a(t) = -12[itex]\pi[/itex](6[itex]\pi[/itex])Cos(6[itex]\pi[/itex]t+([itex]\pi[/itex]/2))
The Attempt at a Solution
The displacement and acceleration are zero, but for some reason when i plug them into my calculator (it is set to radians) i keep getting answers other than zero, any suggestions?