Photoelectric Effect and the conversion ofPlank's constant from V.S to J.S

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The discussion focuses on calculating Planck's constant from a graph of cut-off voltage versus frequency. The slope of the graph, calculated as 4.224x10^-15 V.s, needs to be converted to J.s. The conversion involves using the equation eV = change in kinetic energy, as cut-off voltage represents the maximum kinetic energy of electrons. The relationship between the axes indicates that the gradient will yield the correct units for Planck's constant. Ultimately, the goal is to compare the calculated value with the accepted value of Planck's constant.
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i graphed cut-off voltage verses frequency.
when i figured out plank's constant so when i calculated the slope of the function i got 4.224x10-15. My question is how to convert V.s to J.s for the value of hhereS the question

FINDING A VALUE OF PLANK'S CONSTANT FORM YOUR GRAPH.
calculate the slope of the graph (in V.s)
plank's constant is the slope of a graph of maximum kinetic evergy vs frequency so we need to convert cut-off coltage to maximum kinetic energy. we can use the equation.
eV=change in kinetic energy
because cut-off voltage just stops the most energetic electron.
convert the value of your slope to J.s and compare your value to the accepted value of plank's constant.
 
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If you have plotted KEmax against frequency the units on each axis should be eV (or maybe Joules) and s^-1 (frequency unit)
Can you see what units the gradient of a graph on these axes will be?
 
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