Photoelectric Effect: Find K.E. of Photoelectron in Air, Cs-137

AI Thread Summary
To find the kinetic energy of the photoelectron emitted from the photoelectric effect involving Cs-137, the equation hf = K + Φ is used, where hf represents the energy of the gamma photon, K is the kinetic energy of the photoelectron, and Φ is the work function (34 eV). The challenge lies in determining the frequency of the gamma ray, which is not provided in the problem statement. Participants suggest looking up the frequency of the gamma photon associated with Cs-137 to solve the problem. The discussion emphasizes the need for external research to find the necessary frequency for calculations. Ultimately, the solution hinges on accurately determining the energy of the gamma photon.
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Homework Statement


The gamma photon emitted by the nucleus of the cesium isotope with 137 mass number is absorbed with photoeffect. The absorbing medium is air, assume the work function to be 34 ev. What will be the kinetic energy of the photoelectron in eV?

Homework Equations


hf=K+Φ

The Attempt at a Solution


The equation is simple to use but I don't understand how I can find out the frequency of the gamma ray from the problem statement.

Thank you in advance.
 
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