Photoelectric Effect: Find K.E. of Photoelectron in Air, Cs-137

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SUMMARY

The discussion centers on calculating the kinetic energy of a photoelectron emitted due to the photoelectric effect when a gamma photon from cesium-137 is absorbed in air. The work function is specified as 34 eV, and the relevant equation is hf = K + Φ, where hf represents the energy of the photon, K is the kinetic energy of the photoelectron, and Φ is the work function. Participants emphasize the need to determine the frequency of the gamma ray to solve the problem, suggesting that external resources may provide necessary information.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Knowledge of gamma photon properties
  • Familiarity with the equation hf = K + Φ
  • Basic concepts of work function in photoemission
NEXT STEPS
  • Research the properties of gamma photons emitted by cesium-137
  • Learn how to calculate photon frequency from energy
  • Study the implications of work function in different materials
  • Explore advanced applications of the photoelectric effect in modern physics
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Students studying quantum mechanics, physicists interested in nuclear decay processes, and educators teaching the principles of the photoelectric effect.

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Homework Statement


The gamma photon emitted by the nucleus of the cesium isotope with 137 mass number is absorbed with photoeffect. The absorbing medium is air, assume the work function to be 34 ev. What will be the kinetic energy of the photoelectron in eV?

Homework Equations


hf=K+Φ

The Attempt at a Solution


The equation is simple to use but I don't understand how I can find out the frequency of the gamma ray from the problem statement.

Thank you in advance.
 
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