What is the formula for converting decibels to a power ratio?

AI Thread Summary
To convert decibels to a power ratio, the formula used is based on the logarithmic relationship between power and intensity. In the example provided, a sound measuring 100 dB is converted using the formula 10^(dB/10) to find the power ratio. The confusion arises from understanding how the logarithm is removed, which involves recognizing that the exponent of 10 corresponds to the base of the logarithm used in the calculation. The formula effectively transforms the dB value into a power ratio by applying this exponentiation. Clarification on logarithmic properties can help in understanding this conversion process better.
AgustRunarsson
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Note: I'm sorry if I have to use the template, but I already have the solution, I just do not understand it and need help understanding it.
1. Question: A firework explodes at a 40 metre height and gives off a bang which measures at 100 dB at ground level. What is the power of the sound that comes off the firework?

This is the solution:

xlcdqf.png

I understand what is going on, for the most part.
What I do not understand exactly is at the second part the "100 dB" becomes 10^100dB/10 which removes the log. How? I understand that the exponent is 10 in "10*log" but I don't really understand how the 10 comes from in the exponent of the 10 itself.

Any help would be appreciated. Thanks!
 

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AgustRunarsson said:
What I do not understand exactly is at the second part the "100 dB" becomes 10^100dB/10 which removes the log. How? I understand that the exponent is 10 in "10*log" but I don't really understand how the 10 comes from in the exponent of the 10 itself.

If ##A = B \log_{10} C##, then ##A/B = \log_{10} C##, and ##C =##?
 
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