Physics problem involing a lotus car

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The discussion centers on calculating the distance traveled by a Lotus car given specific parameters, including a drag force of 400N and an average speed of 20 m/s. The mass of the vehicle is 903 kg, with a fuel conversion efficiency of 13%. Initial calculations yield an acceleration of 0.443 m/s² using the formula F=ma. However, participants suggest focusing on work and energy principles, specifically using the equation Work = force * distance, to solve the problem more effectively. The conversation emphasizes the importance of selecting the appropriate equations for the scenario.
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Homework Statement



When the a lotus is driven at average speed of 20 m/s the drag force on the vehicle is 400N. If the average fuel conversion is 13% then calculate the distance traveled by the vehicle.

Mass of Vehicle = 903kg
Volume of fuel tank= 43.5 litre
Density of fuel= 775 kg/m^3
Calorific Value of fuel= 42.7 MJ/kg



Homework Equations



F=ma and V^2= U^2 + 2as



The Attempt at a Solution




(1)400=903a
a= 0.443m/s^2

(2) V^2= U^2 +2as
20^2+2(0.443)s
S= 451.47m
 
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I think you can forget equations of motion. This appears to be about work and energy. Try an equation like...

Work = force * distance
 
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