Pigeonhole Principle & irrational numbers

mndt
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Homework Statement



Let x be an irrational number. Show that the absolute value of the difference between jx and the nearest integer to jx is less than 1/n for some positive integer j not exceeding n.

Homework Equations


The Attempt at a Solution



Ok, I know that it should be solved using pigeonhole Principle

and there is the fact that

for real numbers: 0 <= | jx - [jx] | < 1

specifically for irrational numbers: 0 < | jx - [jx] | < 1

that should make the difference but i can't exactly come up with the correct intervals that form the final conclusion.
 
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I think you are looking at it backwards. It is "n" that is 'given', not j. Given a positive integer, n, divide the interval from 0 to 1 into n equal sized (1/n of course) intervals.
 
HallsofIvy said:
I think you are looking at it backwards. It is "n" that is 'given', not j. Given a positive integer, n, divide the interval from 0 to 1 into n equal sized (1/n of course) intervals.

yes, but considering that 1 <= j <= n we have n different js.

that leaves us with n pigeons (js) and n pigeonholes (intervals). :biggrin: and no useful conclusion.

and why only irrational numbers?!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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