Plane waves, phase difference question

AI Thread Summary
To find the shortest distance along a lightwave with a phase difference of 30 degrees, the wavelength is calculated to be 5000 m using the formula velocity = frequency x wavelength. Since a full wavelength corresponds to a phase difference of 2π radians, a phase difference of π/6 (30 degrees) corresponds to a distance of 5000 m / 12, which equals approximately 416.67 m. Additionally, in 1 microsecond, the phase shift can be calculated, and the number of waves that pass by can be determined using the wave's frequency. The discussion highlights the need for further assistance in solving these aspects of the problem.
goldilocks
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Homework Statement



Consider a lightwave having a phase velocity of 3 x 10^8 m/s and a frequency of 6 x 10^14 hz. What is the shortest distance along the wave between any two points that have a phase difference of 30 degrees ? What phase shift occurs at a given point in 1 microsecond and how many waves have passed by in that time ?

Homework Equations



velocity = frequency x wavelength

The Attempt at a Solution



have calculated that the wavelength is 5000m, by dividing speed of light by the frequency, but am stuck and don't know how to proceec. any help would be amazing, thank you!
 
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When the distance between the two points is equal to the wavelength, the phase difference between the points is 2π. So when the phase difference between the two points is π/6, the distance between the two points is...
 
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